three consecutive numbers where twice the sum of the first 2 is 3 less than 4 times the third
Three consecutive numbers can be represented by n, n+1 and n+2 ....so we have
2[n + (n +1) ]+ 3 = 4(n + 2) simplify
2(2n +1) + 3 = 4n + 8
4n + 5 = 4n + 8
And this has no solution !!!!
