math <3

Quote:

5 log (base 7) x - 2 log (base 7) x

since the log bases are the same you can use the properties of logarithms

a log(x) = log(x^a)

log(y) - log(x) = log(y/x)

using both of these you get

log(base 7, (x^5)/(x^2)) = log(base 7, x^3)