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Alex and Dave shared some apples. Alex had twice as many apples as Dave. When Dave gave 10 apples to Alex, he had 8 times as many apples as Dave in the end. Find the number of apples Alex had at first.

 Apr 29, 2021
 #1
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Let's assume Dave had \(x\) apples at first. 

⇒ Alex had = \(2x\) apples

 

When Dave gave 10 apples to Alex, he had 8 times as many apples as Dave in the end.

∴ According to question, 

 

\(2x+10=8(x-10)\)

\(2x+10=8x-80\)

\(6x=90\)

\(x=15\)

 

Thus, Alex had 30 apples at first.

 Apr 30, 2021

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