Alex and Dave shared some apples. Alex had twice as many apples as Dave. When Dave gave 10 apples to Alex, he had 8 times as many apples as Dave in the end. Find the number of apples Alex had at first.

Tgfromthe4 Apr 29, 2021

#1**+3 **

Let's assume Dave had \(x\) apples at first.

⇒ Alex had = \(2x\) apples

When Dave gave 10 apples to Alex, he had 8 times as many apples as Dave in the end.

∴ According to question,

\(2x+10=8(x-10)\)

\(2x+10=8x-80\)

\(6x=90\)

⇒\(x=15\)

Thus, Alex had **30 apples **at first.

amygdaleon305 Apr 30, 2021