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2x^2+7+57=0

 Oct 31, 2016
edited by Guest  Oct 31, 2016
edited by Guest  Oct 31, 2016
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2x^2+7+57=0     if this is correct, it will not have real solutions....simplify

 

2x^2 + 64   = 0    subtract 64 from both sides

 

2x^2  = - 64     divide both sides by 2

 

x^2  = -32         take the pos/neg square roots

 

x = ± √-32   = ± √ ( -1 * 16 * 2)   =  ± 4i√2

 

 

 

cool cool cool

 Oct 31, 2016

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