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What is the 5th term in the expansion of  (12x3y2−4y)9

 Feb 8, 2020
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5th from what end? 

 

\((12x^3y^2−4y)^9\)

 

\(5th\;term=9C4* (-4y)^4 * (12x^3y^2)^5\\ 9C4*256y^4*12^5*x^{15}*y^{10}\\ 126*256*248832*y^4*x^{15}*y^{10}\\ 8026324992y^{14}x^{15}\)

 

Assuming I made no silly mistakes that is the 5th term from one end.

 

coding:

(12x^3y^2−4y)^9

 
 Feb 8, 2020

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