5th from what end?

\((12x^3y^2−4y)^9\)

\(5th\;term=9C4* (-4y)^4 * (12x^3y^2)^5\\ 9C4*256y^4*12^5*x^{15}*y^{10}\\ 126*256*248832*y^4*x^{15}*y^{10}\\ 8026324992y^{14}x^{15}\)

Assuming I made no silly mistakes that is the 5th term from one end.

coding:

(12x^3y^2−4y)^9