5th from what end?
\((12x^3y^2−4y)^9\)
\(5th\;term=9C4* (-4y)^4 * (12x^3y^2)^5\\ 9C4*256y^4*12^5*x^{15}*y^{10}\\ 126*256*248832*y^4*x^{15}*y^{10}\\ 8026324992y^{14}x^{15}\)
Assuming I made no silly mistakes that is the 5th term from one end.
coding:
(12x^3y^2−4y)^9
