Simplify the following:
b/3 + (2 b)/3 - (5 (b + 1))/6
Put each term in b/3 + (2 b)/3 - (5 (b + 1))/6 over the common denominator 6: b/3 + (2 b)/3 - (5 (b + 1))/6 = (2 b)/6 + (4 b)/6 - (5 (b + 1))/6:
(2 b)/6 + (4 b)/6 - (5 (b + 1))/6
(2 b)/6 + (4 b)/6 - (5 (b + 1))/6 = (2 b + 4 b - 5 (b + 1))/6:
(2 b + 4 b - 5 (b + 1))/6
2 b + 4 b = 6 b:
(6 b - 5 (b + 1))/6
-5 (b + 1) = -5 b - 5:
(6 b + -5 b - 5)/6
Grouping like terms, 6 b - 5 b - 5 = (6 b - 5 b) - 5:
((6 b - 5 b) - 5)/6
6 b - 5 b = b:
(b - 5)/6
