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How many solutions does the system have?

 

y=−2x+1

 

y=−2x^2+1

 

 

Thanks!!!!

 Feb 25, 2019
 #1
avatar+101762 
+2

y = -2x + 1

 

y = -2x^2 + 1

 

Set the y's equal

 

-2x^2 + 1 = - 2x + 1           subtract 1 from both sides

 

-2x^2 = - 2x             multiply both sides by -1

 

2x^2 = 2x       divide both sides by 2

 

x^2 = x     subtract x from both sides

 

x^2 - x = 0       factor

 

x ( x - 1) = 0

 

Setting each factor to 0  and solving for x produces two  solutions at

 

x = 0      and   x =  1

 

 

cool cool cool

 Feb 25, 2019

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