+360 How many solutions does the system have?
y=−2x+1
y=−2x^2+1
Thanks!!!!
+128475 y = -2x + 1
y = -2x^2 + 1
Set the y's equal
-2x^2 + 1 = - 2x + 1 subtract 1 from both sides
-2x^2 = - 2x multiply both sides by -1
2x^2 = 2x divide both sides by 2
x^2 = x subtract x from both sides
x^2 - x = 0 factor
x ( x - 1) = 0
Setting each factor to 0 and solving for x produces two solutions at
x = 0 and x = 1
