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# Math help needed :D

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My brain is a mess today x.x (EDIT: I see that the image won't show very clear sometimes, right clicking and openening a new link helps btw)

The image left is a drawing of a target that can be used with archery. The surface of the target is 18 dm2.

1. Explain why the black part of the circle is 1,5 dm2

2. (Insert Name) shoots 72 times without aiming at the target. If the person misses, it doesn't count and he/she can try again. Prelude how many times she'll hit the black part, grey part and the white part.

3. Another person shoots without aiming. He hit the white part five times. How many times did he hit the grey part?

HeyxJacq  Nov 20, 2017
edited by HeyxJacq  Nov 20, 2017

#1
+93884
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The target is cut into 12 sectors. One sector is black. Since the entire are is 18dm^2

It follows that the black are is 18 / 12 = 1.5dm^2

Expectations:

She'll hit the black part 1/12 of the time.     72/12= about 6 times

She'll hit the white part 3/12  of the time.     3*6= about 18 times

She'll hit the grey part 8/12 of the time.     8*6 = about 48 times

3)

If he hits the white part 5 times he will hit the grey part  $$\frac{5}{3}*8= 13.\dot3 \approx 13\;times$$

Melody  Nov 20, 2017
#1
+93884
+3

The target is cut into 12 sectors. One sector is black. Since the entire are is 18dm^2

It follows that the black are is 18 / 12 = 1.5dm^2

Expectations:

She'll hit the black part 1/12 of the time.     72/12= about 6 times

She'll hit the white part 3/12  of the time.     3*6= about 18 times

She'll hit the grey part 8/12 of the time.     8*6 = about 48 times

3)

If he hits the white part 5 times he will hit the grey part  $$\frac{5}{3}*8= 13.\dot3 \approx 13\;times$$

Melody  Nov 20, 2017