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# Math help plzzzz

+1
300
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+50

http://prntscr.com/ls70ot

Dec 8, 2018

#1
+4330
+1

The first choice and fourth choice.

We could find the least common multiplier, turn things around and get $$x\left(x+3\right)+2=5\left(x+2\right)$$ .

Then, solving, we get $$x=4,\:x=-2$$ and $$\boxed{x=4}$$  as    $$x=2$$ , creates a zero in the denominator.

Dec 8, 2018