Math help plzzzz

The first choice and fourth choice. 

We could find the least common multiplier, turn things around and get $x\left(x+3\right)+2=5\left(x+2\right)$ .

Then, solving, we get $x=4,\:x=-2$ and $\boxed{x=4}$  as    $x=2$ , creates a zero in the denominator.