Which equation is the polar equivalent to the equation y=−√3/3x? θ=π/6 θ=π/3 θ=2π/3 θ=5π/6
y= r sin (theta)
x = rcos (theta)
So
r sin (theta) = [ sqrt (3) / 3 ] * [ r cos (theta) ]
sin (theta) = (1 /sqrt 3) * cos (theta)
sin (theta) / cos (theta) = 1 / sqrt 3
tan (theta) =1 /sqrt 3
arctan (1/sqrt 3) = theta = pi / 6
