We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

#1**+14 **

Okay I misread the problem. Alright.

\(42\frac{1}{6} - 27\frac{3}{5}\)

First off, we want to convert these mixed numbers into improper fractions.

We get \(\frac{42\times6 + 1}{6} - \frac{27\times5 + 3}{5}\), or \(\frac{253}{6} - \frac{138}{5}\).

We need to put both fractions under a common denominator to solve. Let's put both fractions under \(30\), the LCM.

We get \(\frac{1265}{30} - \frac{828}{30}\). Now we can subtract the fractions, giving us \(\frac{437}{30}\).

Converting this back into a mixed number, we get \(14\frac{17}{30}\).

Therefore, our answer is \(\boxed{14\frac{17}{30}}\).

KnockOut Nov 4, 2018

#3**+14 **

An easier way to do this is to subtract the mixed numbers without conversion to an improper fraction. For this to happen, the fraction part of the mixed number in the first number (\(\frac{1}{6}\) in our case) needs to be larger than the \(\frac{3}{5}\).

Let's compare.

\(\frac{1}{6} = \frac{5}{30}\)

\(\frac{3}{5} = \frac{18}{30}\)

\(\frac{18}{30}>\frac{5}{30}\).

Since the second fraction is larger, we need to modify the first fraction to make it larger.

So from \(42\frac{1}{6}\), we are going to take \(1\) (Which is equal to \(\frac{6}{6}\)) out of the \(42\), and add it to the fractions part giving us \(41\frac{7}{6}\)

\(\frac{7}{6} = \frac{35}{30}\).

\(\frac{35}{30}>\frac{18}{30}\)

Now we can subtract easily.

\(41\frac{35}{30} - 27\frac{18}{30} = 14\frac{17}{30}\)

So our answer is yet again \(\boxed{14\frac{17}{30}}\)

KnockOut Nov 4, 2018