In order to unload clay easily, the body of a dump truck must be elevated to at least 45°. The body of a dump truck that is 12 feet long has been raised to 8 feet. Will the clay pour out easily?
Find the area of sector GHJ given that 𝜃 = 40°. Use 3.14 for 𝜋 and round to the nearest tenth.
What is the area of ∆𝐵𝐶𝐷 to the nearest tenth of a square centimeter?
1. The 12 ft can be considered the hypotenuse of a right triangle
And the 8 ft can be considered the leg opposite the angle we are considering
So....to find out if this angle is at least 45°, we have take thw sine inverse of 8/12
So we have
asin (8/12) = the angle ≈ 41.8°.....so....it won't pour out smoothly
2. Area = (3.14) r^2 * (40/ 360) =
(3.14) * 4^2 * 1/9 =
16 * 3.14 / 9 =
5.6 cm^2
3. We have a 30-60-90 right triangle.....the side opposite the 30 degree angle = 10 = base
And the side oposite the 60 degree angle = 10√3 cm = height
So....the area is (1/2) base * height =
(1/2) 10 * 10√3 =
50√3 cm^2 ≈ 86.6 cm^2