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Lines y=(3a+2)x-2 and 2y=(a-4)x+2 are parallel. What is the value of a ?
Let's put BOTH equations in to y = mx+b form first
y=(3a+2)X-2 AND y= (a-4)/2 x + 2/2 if they are parallel, the slopes will be equal , so
(3a+2) = (a-4)/2 then just solve for'a'
3a +2 = a/2 - 2
5a/2 = -4
5a = -8
a = -8/5