The graph of a certain quadratic \(y = ax^2 + bx + c\) is a parabola with vertex \( (-4,0)\) which passes through the point (1,-75). What is the value of a?
Im not sure if this is right or not but I had a go:
y=ax2+bx+c
use vertex/turning point form
y=a(x-h)2+k
sub in vertex
y=a(x+4)2
sub in point values and solve for a
-75=a(1+4)2
-75=25a
a=-3
Hope this helps.
That is correct!
+4622 
