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Given $\delta(x) = 3x + 8$ and $\phi(x) = 8x + 7$, what is $x$ if $\delta(\phi(x)) = 7$?

Guest Nov 14, 2014

Best Answer 

 #1
avatar+90023 
+5

We have

3[8x + 7 ] + 8 = 7   simplify

24x + 21 + 8  = 7

24x + 29  = 7    subtract 29 from both sides

24x = -22         divide both sides by 24

x = -22/24 = -11/12

 

CPhill  Nov 14, 2014
 #1
avatar+90023 
+5
Best Answer

We have

3[8x + 7 ] + 8 = 7   simplify

24x + 21 + 8  = 7

24x + 29  = 7    subtract 29 from both sides

24x = -22         divide both sides by 24

x = -22/24 = -11/12

 

CPhill  Nov 14, 2014

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