P(G(a)) = 4 + 2√[(4-3x) +2] = 4 + 2√(6-3x )
Note that (6 - 3x) must be ≥ 0
So......
6 - 3x ≥ 0 add 3x to both sides
6 ≥ 3x divide both sides by 3
2 ≥ x → x ≤ 2
So....."a" cannot be > 2
So, what do I write for a?
The largest value that "a" can assume is 2.....