Hello could you please tell me the answer and the work for -3x^-4y^0
-3x^-4y^0
Simplify the following: (-3 x)^(-4 y^0)
y^0 = 1: (-3 x)^(-41)
Multiply each exponent in -3 x by -4: (1)/((-3)^4 x^4)
(-3)^4 = (-1)^4×3^4 = 1×3^4: 1/(3^4 x^4)
3^4 = (3^2)^2: 1/((3^2)^2 x^4)
3^2 = 9: 1/(9^2 x^4)
9^2 = 81: Answer: |1/(81x^4)
