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ABC = A! + B! + C!

Cannot have 6, 7, 8, 9 as digits

At least one digit to be equal to 5

Exactly one digit is equal to 5

Guest Apr 26, 2019

#1**+1 **

I don't think there is a solution for this using the "factorial function"!. However, there is a solution using the "Gamma function". It gives the following solution:

A*B*C =A! + B! + C!, solve for A, B, C

where: **A ≈ 4.39056.... and B = -53/10 ≈ -5.30000 and C = -17/10 ≈ -1.70000**

**Note: This is courtesy of: Mathematica 11 Home Edition.**

Guest Apr 26, 2019