Find (f*g)(x) where f(x)= 1/x+1 and g(x)= -1/x.
(f*g)(x) literally means that we are multiplying the functions f and g together...so we have
1 / x + 1 * - 1 /x = -1/x^2 - 1/x
If "f" is supposed to be 1 / [x + 1]......then we have
1 / [x + 1] * -1/x = -1/ [ x (x + 1) ] = -1/ [x^2 + x ]
