Find the equation of the circle centered at $(1,-4)$ with radius 3. Write your equation in the form "$(x - h)^2 + (y - k)^2 = r^2$"

can u help me with this? I don't know how to solve this and I would like help please!

Guest Feb 1, 2021

#1**0 **

The equation of a circle is written as \((x-h)^2+(y-k)^2=r^2\) where \((h,k)\) are the coordinates of the center of the circle and \(r\) is the radius of the circle.

The center of this particular circle is located at \((1,-4)\), so \(h=1\) and \(k=-4\). The radius is already given as 3.

Equation of circle: \((x-1)^2+(y+4)^2=9\)

I hope this explanation made sense to you!

Guest Feb 1, 2021