solve (t-i)^2+12=-7(t-1)
I assume the first term is meant to be (t-1)^2. If so:
(t - 1)^2 + 12 = -7(t-1)
Add 7(t -1) to both sides:
(t - 1)^2 + 7(t - 1) + 12 = 0
This factors as
(t - 1 + 3)(t - 1 + 4) = 0
or (t + 2)(t + 3) = 0
so t = -2 or t = -3
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