Find f^-1 for the function f(x)=3(sqrt x-2) +8
Just letting you know the three is like above on top of the square root..
+129840 f(x)=3(sqrt x-2) +8
Write this as
y = ∛ [x - 2] + 8 the idea is to get x by itself.......subtract 8 from both sides
y - 8 = ∛ [x - 2] cube each side
( y - 8)3 = x - 2 add 2 to both sides
(y - 8)3 + 2 = x "exchange" x and y
(x - 8)3 + 2 = y and, for y, write f-1(x)
(x - 8)3 + 2 = f-1(x)
