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Solve (n+3)(n+2)! / (n+1)! =30

 Sep 26, 2015
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(n+3)(n+2)! / (n+1)! = 30     ....   note...  (n+2)! / (n + 1)! =  (n + 2)  ......so we have

 

(n+ 3) (n + 2) = 30

 

n^2 +5n + 6 = 30

 

n^2 + 5n - 24  = 0       factor  

 

(n + 8) (n - 3)  = 0      so...n = -8    or n = 3     reject -8, since this would produce a negative factorial and factorials only apply to non-negative integers  [ and, in advanced math courses, positive fractions, as well ]

 

So....n = 3

 

 

cool cool cool

 Sep 26, 2015

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