+9479 Again, the standard form of a line is Ax + By = C where A is a positive integer, and B and C are integers.
Using the point (-2, -3) and the slope \(\frac12\) , the equation of the line in point-slope form is:
y - -3 = \(\frac12\)(x - -2)
y + 3 = \(\frac12\)(x + 2)
Multiply both sides of the equation by 2 .
2(y + 3) = 1(x + 2)
Distribute.
2y + 6 = x + 2
Subtract 2y from both sides.
6 = x - 2y + 2
Subtract 2 from both sides.
4 = x - 2y
x - 2y = 4
+9479 Again, the standard form of a line is Ax + By = C where A is a positive integer, and B and C are integers.
Using the point (-2, -3) and the slope \(\frac12\) , the equation of the line in point-slope form is:
y - -3 = \(\frac12\)(x - -2)
y + 3 = \(\frac12\)(x + 2)
Multiply both sides of the equation by 2 .
2(y + 3) = 1(x + 2)
Distribute.
2y + 6 = x + 2
Subtract 2y from both sides.
6 = x - 2y + 2
Subtract 2 from both sides.
4 = x - 2y
x - 2y = 4
+444 If you need help understanding slope and how to present anything related to it go here it givs many useful tips and teaches with an instructor on video: https://www.khanacademy.org/math/algebra/two-var-linear-equations#slope
You won't regret it. I have found this soo helpful to get out of a time of crisis relating to math.
+700 Oh my god, i am so sorry i did not mean to reply to your comment Hiylin Link, I mean to post a new answer and sorry if i offend you in anyway :(
Tip for the person who posted this question:
The form of standard form is ax+by=c
so you should just plug in values from the slope intercept equation, and put it in a way that would fit the standard form.
Slope intercept is y=mx+B
and thus if you have a line that contains a slope of 1/2 and passes through the point of (-2,3), you would need to find your equation first, and put it into slope intercept, and then change it and put it as standard form!
+444 I'm aware of that my intrervine was actually for the point of giving futre refrence, (Just because the answer came out correct dosen't mean we stop helping?) In mathmathics you can't just stop at the right answer...
Need help again
