+0  
 
0
792
4
avatar+14 

Solve for y, and justify each step.

0.5x - 0.75y = -2

 Sep 15, 2016

Best Answer 

 #4
avatar+14985 
+10

Solve for y, and justify each step.

0.5x - 0.75y = -2

 

\(0.5x - 0.75y = -2 \)          [ * (-1)

 

\(-0.5x + 0.75y = 2 \)          [ + 0.5x

 

\(0.75y = 2+0.5x\)              [ / 0.75

 

\(y= \frac{2+0.5x}{0.75}\)    [Computing counter by denominator

 

\(y= 2\frac{2}{3} +\frac{2}{3}x \)

 Sep 15, 2016
 #1
avatar
0

Solve for y:
0.5 x-0.75 y = -2

0.5 x-0.75 y = x/2-(3 y)/4:
x/2-(3 y)/4 = -2

Subtract x/2 from both sides:
-(3 y)/4 = 1/2 (-4-x)

Multiply both sides by -4/3:
Answer: |y = (2 (x+4))/3

 Sep 15, 2016
 #2
avatar+14 
0

Solve for y:

 

0.5x-0.75y = -2  |  Given

-0.75y = -2-0.5x  |  Subtraction Property of Equality

y = 2.6+0.6x  |  Division Property of Equality

 

 

Sorry if it's wrong. I think that's how you'd solve it though.

(Also, the decimals are rounded.)

 Sep 15, 2016
edited by Guest  Sep 15, 2016
edited by Guest  Sep 15, 2016
edited by Guest  Sep 15, 2016
 #3
avatar+129840 
+5

0.5 x-0.75 y = -2       subtract  0.5x from both sides

 

-0.75 y   =   - 0.5 x   - 2        multiply through by  -1

 

0.75y  = 0.5x  + 2        change the decimals to fractions

 

(3/4)y   = (1/2)x  + 2      multiply both sides b6y (4/3)

 

y  = (2/3)x + 8/3

 

 

cool cool cool

 Sep 15, 2016
 #4
avatar+14985 
+10
Best Answer

Solve for y, and justify each step.

0.5x - 0.75y = -2

 

\(0.5x - 0.75y = -2 \)          [ * (-1)

 

\(-0.5x + 0.75y = 2 \)          [ + 0.5x

 

\(0.75y = 2+0.5x\)              [ / 0.75

 

\(y= \frac{2+0.5x}{0.75}\)    [Computing counter by denominator

 

\(y= 2\frac{2}{3} +\frac{2}{3}x \)

asinus Sep 15, 2016

5 Online Users

avatar
avatar