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What is 40/17 in fraction form ?
Clicking the link ∑LaTeX above.\(\)
Delete in case "x = {-b \pm \sqrt{b^2-4ac} \over 2a}"
Write in the box 40/17= \frac{40}{17} Give OK
It appears \(\) \( 40/17= \frac{40}{17} \)
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asinus :- )
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\(\frac{40}{17}\\ = \frac{34 + 6}{17}\\ = \frac{34}{17}+\frac{6}{17}\\ = 2+\frac{6}{17}\\ = 2\frac{6}{17}\)
Same as EighthMersennePrime's answer.