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How can you add brackets in this question?
5x3-2x10-3=47
 Nov 25, 2013
 #1
avatar+118653 
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How can you add brackets in this question?
5x3-2x10-3=47

do you mean 5x^3 - 2x^10 - 3 = 47 ?

If you want to factorise properly you would change it to
You'd change it to 2x^10 - 5x^3 +50 = 0
then look for factors.
The only possible rational factors are +- ( 1,2,5,25,50,0.5,2.5, 12.5) Using rational root theorem

Using remainder theorem I can see that;
no minus one will work so that halves the possibilities
2 or bigger won't work
1 doesn't work
0.5 doesn't work
so there are no rational roots so I can't factorise

However, I suppose you could say

5x^3 - 2x^10 - 3 = 47
x^3(5 - 2x^7) = 50
It wouldn't be very useful for anything but it does have brackets and it is true.
 Nov 25, 2013
 #2
avatar+118653 
0
How can you add brackets in this question?
5x3-2x10-3=47

I just realised what your question really was sorry, I got a bit carried away.

maybe just

5x3 - 2x10 -3 = 47

5x3 -3 -2x10 = 47

5x3 - 1x3 -2x10 = 47

5 lots of 3 takeaway 1 lot of 3 = (5-1) lot of 3 = 3 lots of (5-1) = 3 x (5-1)

5x3 - 1x3 -2x10 = 47
3 x (5-1) - 2 x10 = 47

Is that more what you had in mind?
 Nov 25, 2013

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