What is the rectangular form of the polar equation?
r−rcosθ=6
x=112y2−36
x=112y2−3
x=12y2−36
x=12y2−3
r - rcos θ = 6
r - r ( x/r) = 6
r - x = 6
r = x + 6 square both sides
r^2 = x^2 + 12x + 36
x^2 + y^2 = x^2 + 12x + 36
y^2 = 12x + 36
12x = y^2 - 36 divide through by 12
x = (1/12)y^2 - 3