Mr lee had some grains. He sold 380 kg of the grains. By feeding the chicken in his farm with the same amount of grains each day, he would use up all his remaining grains in 50 days. If in the first 30 days, the chicken were fed 1/8 of the original amount of the grains, how many kg of grains did the farmer feed the chicken on the 1st 30 days?
Mr lee had some grains. He sold 380 kg of the grains. By feeding the chicken in his farm with the same amount of grains each day, he would use up all his remaining grains in 50 days. If in the first 30 days, the chicken were fed 1/8 of the original amount of the grains, how many kg of grains did the farmer feed the chicken on the 1st 30 days?
originally he had 380+x kg
50d=x (1)
30d=1/8*(380+x) (2)
30*8d = 380+x
240d = 380+x
sub in (1)
240d =380 +50d
190d = 380
d=2
so each day the chickens eat 2 kg
So in the first 30 days the farmer fed the chickens 60Kg
Mr lee had some grains. He sold 380 kg of the grains. By feeding the chicken in his farm with the same amount of grains each day, he would use up all his remaining grains in 50 days. If in the first 30 days, the chicken were fed 1/8 of the original amount of the grains, how many kg of grains did the farmer feed the chicken on the 1st 30 days?
originally he had 380+x kg
50d=x (1)
30d=1/8*(380+x) (2)
30*8d = 380+x
240d = 380+x
sub in (1)
240d =380 +50d
190d = 380
d=2
so each day the chickens eat 2 kg
So in the first 30 days the farmer fed the chickens 60Kg