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 Math Problem #1

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Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph in the same direction as car A. At what time will car B pass car A?

 

Justify.

 May 9, 2015

Best Answer 

 #1
avatar+118677 
+8

speed=distance/time

 

distance = speed *time

car 1

distance = 30*t

car 2

distance = 40(t-1)

they will be at the same spot when

30t=40(t-1)      

30t=40t-40

-10t=-40

t=4 hours

t=

 May 9, 2015

4+0 Answers

 #1
avatar+118677 
+8
Best Answer

speed=distance/time

 

distance = speed *time

car 1

distance = 30*t

car 2

distance = 40(t-1)

they will be at the same spot when

30t=40(t-1)      

30t=40t-40

-10t=-40

t=4 hours

t=

Melody May 9, 2015
 #3
avatar+129852 
+5

Notice that when Car B starts, car A has a 30 mile "lead.' And car B cuts this disttance by 10 miles every hour. So....it takes 3 hours for B to catch A. so....3 hrs. later than 10 AM  = 1 PM.....and that's when B passes A.

 

  

 May 9, 2015
 #4
avatar+870 
+5

Good job.

You both have earned a cookie:

 May 9, 2015
 #5
avatar+129852 
0

Thanks, EinsteinJr......I'm gettin' hungry, too.....!!!!

 

 

  

 May 9, 2015

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