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Hi, I'm not quite sure how to do this. Could someone help me understand please?
Given positive integers x and y such that 2 x^2 y^2 + 4y^3 = 149 + 3x^2, what is the value of x+y?

I think I might have to factor parts of this different ways but I don't know how to get an equation where I could do that. 
Thanks! :)

 Dec 13, 2019
 #1
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2x^2y^2 + 4y^3  =  149 + 3x^2      reaarange as

 

2x^2y^2  - 3x^2  + 4y^3  - 149 = 0        

 

WolframAlpha does not  show any integer solutions for x, y   :

 

https://www.wolframalpha.com/input/?i=2x%5E2y%5E2++-+3x%5E2++%2B+4y%5E3++-+149+%3D+0++++++++

 

 

cool cool cool

 Dec 13, 2019
 #2
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Huh ok, well thanks!

Guest Dec 13, 2019
 #3
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Ok I looked at the answer on my math program and it said to subtract 6 from both sides and then factor... so after subtracting 6 they got 
(x^2 + 2)(2y^3 - 3) = 143

and went from there.
It seems to work... 
huh

Guest Dec 13, 2019

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