Camy made a list of every possible distinct five-digit positive integer that can be formed using each of the digits 1, 3, 4, 5 and 6 exactly once in each integer. What is the sum of the integers on Camy's list?
+770 the average value of 1, 3, 4, 5, and 6 = 4.4
multiply this by 11,111 (one for each tens place in the value)
and your answer is 4.4 * 11,111 = 5,866,608.
+129852 Here's my best attempt !!!
Look at the "ones" digit......let's suppose it is "1"
Then...we have 4! = 24 ways to arrange the other leading digits with each 5 digit integer ending in "1"
And it will be the same for each of the other integers ending in 3, 4 , 5 or 6
So the sum of the digits in the "ones" place will be
24 ( 1 + 3 + 4 + 5 + 6) = 456
And the same will happen in the "tens," "hundreds," "thousands," and "ten thousands" places
So....the sum will be
456 ( 1 + 10 + 100 + 1000 + 10000) =
456 ( 11111) =
5,066,616
