How to solve this:
4(3x+2)-3(2x-1)=35 ? Please help. Could you tell me in details as well how you did it?
Solve for x:
4 (3 x+2)-3 (2 x-1) = 35
-3 (2 x-1) = 3-6 x:
3-6 x+4 (3 x+2) = 35
4 (3 x+2) = 12 x+8:
12 x+8-6 x+3 = 35
Grouping like terms, 12 x-6 x+3+8 = (-6 x+12 x)+(3+8):
(-6 x+12 x)+(3+8) = 35
12 x-6 x = 6 x:
6 x+(3+8) = 35
3+8 = 11:
6 x+11 = 35
Subtract 11 from both sides:
6 x+(11-11) = 35-11
11-11 = 0:
6 x = 35-11
35-11 = 24:
6 x = 24
Divide both sides of 6 x = 24 by 6:
(6 x)/6 = 24/6
6/6 = 1:
x = 24/6
The gcd of 24 and 6 is 6, so 24/6 = (6×4)/(6×1) = 6/6×4 = 4:
Answer: |x = 4
