an integer from 100 through 999, inclusive , is to be chosen at random. What is the probability that the number chosen will have 0 as at least 1 digit?
+37099 171/900 is what I come up with....how 'bout you?
Let's look at the 100's
100 101 102 103 104 105 106 107 108 109 110 120 130 140 150 160 170 180 190
19 for each of the 100s (100 200 300 etc)
19 x 9 = 171 out of 900 choices (100-999 inclusive)
+37099 171/900 is what I come up with....how 'bout you?
Let's look at the 100's
100 101 102 103 104 105 106 107 108 109 110 120 130 140 150 160 170 180 190
19 for each of the 100s (100 200 300 etc)
19 x 9 = 171 out of 900 choices (100-999 inclusive)
