Math Problem .

In △CDE , DE=c=14 , CE=d=9 , and ∠$\epsilon =71^o$ .
What is the length of CD=e?

Hello Guest!

$e^2=c^2+d^2-2cd\cdot cos(\epsilon)$        cosine

$e=\sqrt{14^2+9^2-2\cdot 14\cdot 9\cdot cos(71^o)}$

$e=13.96269...$

The length of CD is 13.96269...

  !