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The hypotenuse of an isosceles right triangle is 4sqrt(2) units. How many square units are in the area of the triangle?

 Jul 30, 2020
 #1
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we square 4sqrt2 to get 32 and it is isocles so the sides are sqrt16 and sqrt16 and the area is 4*4/2=4*2=8

 Jul 30, 2020
edited by jimkey17  Jul 30, 2020
 #2
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Use Pythagoras's Theorem:

H^2 =2S^2

[4sqrt(2)]^2 = 2S^2

32 = 2S^2

S^2 =32 / 2 = 16

S = Sqrt(16) = 4 - The 2 sides of an isosceles Right triangle

Area =[Base x Height] / 2

Area =[4 x 4] / 2 = 8 units^2, or use Heron's Formula to find the same.

 Jul 30, 2020
 #3
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we square 4sqrt2 to get 32 and it is isocles so the sides are sqrt16 and sqrt16 and the area is 4*4/2=4*2=8

 Jul 30, 2020
 #4
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The hypotenuse of an isosceles right triangle is 4sqrt(2) units. How many square units are in the area of the triangle?

 

A = ( 4√ 2 )2 / 4 = 8 u2

 Jul 31, 2020

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