Math Problem.

we square 4sqrt2 to get 32 and it is isocles so the sides are sqrt16 and sqrt16 and the area is 4*4/2=4*2=8

Use Pythagoras's Theorem:

H^2 =2S^2

[4sqrt(2)]^2 = 2S^2

32 = 2S^2

S^2 =32 / 2 = 16

S = Sqrt(16) = 4 - The 2 sides of an isosceles Right triangle

Area =[Base x Height] / 2

Area =[4 x 4] / 2 = 8 units^2, or use Heron's Formula to find the same.

we square 4sqrt2 to get 32 and it is isocles so the sides are sqrt16 and sqrt16 and the area is 4*4/2=4*2=8

The hypotenuse of an isosceles right triangle is 4sqrt(2) units. How many square units are in the area of the triangle?

A = ( 4√ 2 )² / 4 = 8 u²