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Find all m for which  \( \sqrt{17 - \sqrt{m}} \)

is an integer.

 

I have no idea where to start with this, can you guys explain as well as sovling this, how do these problems in the future.

 Jun 19, 2016
 #1
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0

Solve for m:
sqrt(17-sqrt(m)) = 0

 

Square both sides:
17-sqrt(m) = 0

 

Subtract 17 from both sides:
-sqrt(m) = -17

 

Multiply both sides by -1:
sqrt(m) = 17

 

Raise both sides to the power of two:
Answer: | m = 289

 Jun 19, 2016
 #2
avatar+23251 
+5

Following what guest has shown:

Since solving  sqrt( 17 - sqrt( m ) )  =  0  results in the value:  m = 289,

also solve:      sqrt( 17 - sqrt( m ) )  =  1  to get  m = 256,

and                sqrt( 17 - sqrt( m ) )  =  2  to get  m = 169,

and                sqrt( 17 - sqrt( m ) )  =  3  to get  m = 64,

and                sqrt( 17 - sqrt( m ) )  =  4  to get  m = 1.

 

You needn't go any farther, because imaginary numbers will be involved.

 Jun 19, 2016
 #3
avatar+33653 
0

Let n = sqrt{17 - sqrt{m}},  where n is an integer.

n^2 = 17 - sqrt{m}

sqrt{m} = 17 - n^2

m = (17 - n^2)^2

Now let n be 1, 2, 3 etc. until 17 - sqrt{m} is no longer positive.

 

 

(I see geno has beaten me to it)

.

 Jun 19, 2016

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