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In a certain Algebra 1 class of 20 students, 8 of them play soccer and 7 of them play football. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays soccer or football?

 May 24, 2023
 #1
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The number of students who play soccer or football is 8 + 7 - 8 = 9. The probability that a student chosen randomly from the class plays soccer or football is 9/20.

 May 24, 2023
 #2
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There are 20 students in the class.

 

20  -  8 ==12 students who play either soccer or football

 

Let x be the number of students who play both sports.

 

7 + 8 - x ==12

15 - x ==12

x ==15 - 12 =3 students who play both sports

 

The probability that a randomly chosen student play either soccer or football is:

 

[7 + 8 - 3] / 20 ==12 / 20 ==3/5

 May 24, 2023

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