In a certain Algebra 1 class of 20 students, 8 of them play soccer and 7 of them play football. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays soccer or football?
The number of students who play soccer or football is 8 + 7 - 8 = 9. The probability that a student chosen randomly from the class plays soccer or football is 9/20.
There are 20 students in the class.
20 - 8 ==12 students who play either soccer or football
Let x be the number of students who play both sports.
7 + 8 - x ==12
15 - x ==12
x ==15 - 12 =3 students who play both sports
The probability that a randomly chosen student play either soccer or football is:
[7 + 8 - 3] / 20 ==12 / 20 ==3/5
