In a certain Algebra 1 class of 20 students, 8 of them play soccer and 7 of them play football. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays soccer or football?

Guest May 24, 2023

#1**0 **

The number of students who play soccer or football is 8 + 7 - 8 = 9. The probability that a student chosen randomly from the class plays soccer or football is 9/20.

Guest May 24, 2023

#2**0 **

There are 20 students in the class.

20 - 8 ==12 students who play either soccer or football

Let x be the number of students who play both sports.

7 + 8 - x ==12

15 - x ==12

x ==15 - 12 =3 students who play both sports

The probability that a randomly chosen student play either soccer or football is:

**[7 + 8 - 3] / 20 ==12 / 20 ==3/5**

Guest May 24, 2023