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0=x^4+5x^3-15x^2-5x+14

 

Anyone who can help me solve this? 

 Oct 21, 2017

Best Answer 

 #2
avatar+96275 
+1

x^4+5x^3-15x^2-5x+14  = 0       

 

Write -15x^2  as   -14x^2  - x^2

 

x^4+5x^3-14x^2 - x^2 -5x+14 = 0

 

x^2(x^2+ 5x - 14) - 1(x^2 + 5x - 14) = 0

 

(x^2 - 1) ( x^2 + 5x - 14) = 0

 

(x + 1) (x - 1) (x + 7) ( x - 2)  = 0

 

Set each factor to 0  and solve for x  and we get that x = -1, 1, - 7 or 2

 

 

cool cool cool

 Oct 21, 2017
 #1
avatar+27480 
0

This factorises as:

 

(x - 1)(x + 1)(x - 2)(x + 7) = 0

 

I'm sure you can take it from there!

 Oct 21, 2017
 #2
avatar+96275 
+1
Best Answer

x^4+5x^3-15x^2-5x+14  = 0       

 

Write -15x^2  as   -14x^2  - x^2

 

x^4+5x^3-14x^2 - x^2 -5x+14 = 0

 

x^2(x^2+ 5x - 14) - 1(x^2 + 5x - 14) = 0

 

(x^2 - 1) ( x^2 + 5x - 14) = 0

 

(x + 1) (x - 1) (x + 7) ( x - 2)  = 0

 

Set each factor to 0  and solve for x  and we get that x = -1, 1, - 7 or 2

 

 

cool cool cool

CPhill Oct 21, 2017

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