+0  
 
0
152
1
avatar

Find all solutions of the equation 2cos3x=1 in the interval [0,π).

Guest Feb 18, 2017
 #1
avatar+87301 
0

2cos3x = 1       divide by 2

 

cos (3x)  = 1/2

 

Now 

 

cos (3x)  = 1/2  at   3x =  pi/3, 5pi/3 , 7pi/3, ......so

                               

                                 x =  pi/9, 5pi/9,  7pi/9

 

 

 

cool cool cool

CPhill  Feb 18, 2017

14 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.