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Find all solutions of the equation 2cos3x=1 in the interval [0,π).

Guest Feb 18, 2017
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2cos3x = 1       divide by 2

 

cos (3x)  = 1/2

 

Now 

 

cos (3x)  = 1/2  at   3x =  pi/3, 5pi/3 , 7pi/3, ......so

                               

                                 x =  pi/9, 5pi/9,  7pi/9

 

 

 

cool cool cool

CPhill  Feb 18, 2017

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