if angle θ lies in quadrant II. (sinθ=3/4). what is cos θ?
Solve for θ which equals 48.590
If θ = 48.590
cosθ=0.66144 which is negative in the second quadrant
cos θ = -√[4^2 - 3^2] / 4 = - √7 / 4 [exact value]
Thanks fellow guest for working it out
