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The average of the $N$ integers

\[ N+1, N+2, N+3, \ldots 2N \]

is 80.  What is N?

 Jan 25, 2021
 #1
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Using the formula (a+b)/2*n

 

we have $a$ as the first term

and $b$ as the last term

$(3N+1)/2*N=80*N$

 

Since it is average we have to multiply by the amount of terms

Solving we get $N=53$

 Jan 25, 2021

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