+956 A walking tour of the park is going to be offered as an option to visitors. Shelley, Hattie and Giffin are assigned the task of determining information about the tour. They place a grid over a map of the park and determine the locations of the main areas as follows:
Origin of Fun: (0, 0)
Quadratics in Motion: (-7, 6)
Towers of Trigonometry: (-2, 14)
The Food Equation: (5, 8)
A scale of 1 square to 60 m is used for the grid.
Determine the total distance (in meters) that would be traveled on a tour that goes from The Origin of Fun, to Quadratics in Motion, to Tower of Trigonometry, to The Food Equation and then back to The Origin of Fun.
Provide the mathematical formulas & calculations to support your answer.
Dtermine what geometric shape is formed by the path traced in the walking tour.
Provide the additional, necessary, mathematical formulas & calculations to support your answer.
+129840 Distance Origin of Fun: (0, 0) → Quadratics in Motion: (-7, 6)
sqrt [ (-7)^2 + 6^2 ] = sqrt [49 + 36] = sqrt [85]
Distance Quadratics in Motion: (-7, 6) → Towers of Trigonometry: (-2, 14)
sqrt [ (-7 - - 2)^2 + (14 - 6)^2 ] = sqrt [(-5)^2 + 8^2] = sqrt [25 + 64] sqrt [89]
Distance Towers of Trigonometry: (-2, 14) → The Food Equation: (5, 8)
sqrt [ (-2- 5)^2 + (14 - 8)^2 ] = sqrt [49 + 36] = sqrt [85]
Distance The Food Equation: (5, 8) → Origin of Fun: (0, 0)
sqrt [ (5 )^2 + ( 8)^2 ] = sqrt [25 + 64] = sqrt [89]
Total Distance = 60 * [ 2sqrt(85) + 2sqrt(89)] ≈ 2238 m
The geometric shape is a parallelogram..... pairs of opposite sides / angles are equal.......
Graph :
