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evaluate the expression when k = -4 |k - 2| x |3k| -1

 Sep 14, 2016

Best Answer 

 #1
avatar+118654 
+5

k = -4 |k - 2| x |3k| -1

 

First I will do it the super long way.

 

I am going to split this into bits

k>=2

0<x<2

k<=0


\(If \;k\ge2 \;then\\ k = -4 |k - 2| x *|3k| -1\\ k=-4(k-2)*3k-1\\ k=-12k(k-2)-1\\ k=-12k^2+24k-1\\ 0=-12k^2+23k-1\\ k=\frac{-23\pm \sqrt{23^2-4*-12*-1}}{2*-12}\\ k=\frac{-23\pm \sqrt{528-48}}{-24}\\ k=\frac{-23\pm \sqrt{480}}{-24}\\ k=\frac{-23\pm 4\sqrt{30}}{-24}\\\)

 

\(k\approx\frac{-23\pm 21.9}{-24}\\ \text{neither of these answers are greater or equal to 2 so no solution here}\)

 

 

If  0<x<2

\(k = -4 |k - 2| * |3k| -1\\ k = -4*-(k - 2) * 3k -1\\ k = 12k(k - 2) -1\\ k = 12k^2-24k -1\\ 0 = 12k^2-25k -1\\ k=\frac{25\pm\sqrt{625+48}}{24}\\ k=\frac{25\pm\sqrt{625+48}}{24}\\ k \approx \frac{25\pm25.9}{24}\\ \text{Neither of these answers are between 0 and 2. No solutions here either.}\)

 

\(If \;\; k\le0 \;\;then\\ k=-4|k-2|*|3k|-1\\ k=4(k-2)*-3k-1\\ k=-12k(k-2)-1\\ k=-12k^2+24k-1\\ 0=-12k^2+23k-1\\ 0=12k^2-23k+1\\ k=\frac{23\pm\sqrt{529-48}}{24}\\ k=\frac{23\pm\sqrt{481}}{24}\\ k\approx\frac{23\pm21.9}{24}\\ \mbox{No solution here either }\)

 

No solutions      sad

 Sep 14, 2016
 #1
avatar+118654 
+5
Best Answer

k = -4 |k - 2| x |3k| -1

 

First I will do it the super long way.

 

I am going to split this into bits

k>=2

0<x<2

k<=0


\(If \;k\ge2 \;then\\ k = -4 |k - 2| x *|3k| -1\\ k=-4(k-2)*3k-1\\ k=-12k(k-2)-1\\ k=-12k^2+24k-1\\ 0=-12k^2+23k-1\\ k=\frac{-23\pm \sqrt{23^2-4*-12*-1}}{2*-12}\\ k=\frac{-23\pm \sqrt{528-48}}{-24}\\ k=\frac{-23\pm \sqrt{480}}{-24}\\ k=\frac{-23\pm 4\sqrt{30}}{-24}\\\)

 

\(k\approx\frac{-23\pm 21.9}{-24}\\ \text{neither of these answers are greater or equal to 2 so no solution here}\)

 

 

If  0<x<2

\(k = -4 |k - 2| * |3k| -1\\ k = -4*-(k - 2) * 3k -1\\ k = 12k(k - 2) -1\\ k = 12k^2-24k -1\\ 0 = 12k^2-25k -1\\ k=\frac{25\pm\sqrt{625+48}}{24}\\ k=\frac{25\pm\sqrt{625+48}}{24}\\ k \approx \frac{25\pm25.9}{24}\\ \text{Neither of these answers are between 0 and 2. No solutions here either.}\)

 

\(If \;\; k\le0 \;\;then\\ k=-4|k-2|*|3k|-1\\ k=4(k-2)*-3k-1\\ k=-12k(k-2)-1\\ k=-12k^2+24k-1\\ 0=-12k^2+23k-1\\ 0=12k^2-23k+1\\ k=\frac{23\pm\sqrt{529-48}}{24}\\ k=\frac{23\pm\sqrt{481}}{24}\\ k\approx\frac{23\pm21.9}{24}\\ \mbox{No solution here either }\)

 

No solutions      sad

Melody Sep 14, 2016
 #2
avatar+33653 
0

No real solutions:

 

 Sep 14, 2016
 #3
avatar+118654 
+5

Lets look at it a different way.

 

k = -4 |k - 2| x |3k| -1

 

\(k = -4 |k - 2| x* |3k| -1\)

 

3k and  (k-2)  are both positve  when  k>2

3k and  (k-2)  are both negative  when  k<0

 

so for    0<k<2  the equation becomes

\(k = -4 (k - 2) (3k) -1\\ k = -12k (k - 2) -1\\ k = -12k^2 +24k -1\\ 0= -12k^2 +23k -1\\ \text{Consider the parabola}\\ y= -12k^2 +23k -1\\ \)

This is a concave down parabola

axis of sym     y= -23/-24  =  23/24    this is between 0 and 2

when k=0   y=-1 

when k=2  y = -48+46-1<0

So no solutions here.

 

Between k=0 and k=2

3k >=0 and  (k-2) <=0  

so the equation becomes

 

\(k = 4 (k - 2) (3k) -1\\ k = 12k (k - 2) -1\\ k = 12k^2 -24k -1\\ 0= 12k^2 -25k -1\\ \text{Consider the concave up parabola}\\ y= 12k^2 -25k -1\\ \text{axis of symmetry=25/24 and this is between 0 and 2}\\ \text{When k=0 y=-1, when k=2 y=48-50-1=-3}\\ \text{this means that between k= 0 and k=2 the y value is always negative }\\\)

 

No solutions here either.

 

Here is the graph

 

https://www.desmos.com/calculator/moids6hkw3

 

 

 Sep 14, 2016

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