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P is the point of intersection of the unit circle and the line segment joining the origin and the point (3,-2). Find the coordinates for P.

 

Could someone help me out with this question with work shown, please? 

 Dec 31, 2018
 #1
avatar+98005 
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We can find P  by finding the unit vector for (3, - 2)

 

This is given by:

 

( 3 /  √ [ 3^2 + (-2)^2 ]  ,   -2 /  √  [ 3^2 + (-2)^2 ]  )   =

 

( 3 / √13  , - 2 /  √13)  =  P 

 

 

cool cool cool

 Dec 31, 2018

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