What is the rate of change from 2003 to 2013 with the data points being 7930(2003) and 9372(2013)? I also need a way to express it in a linear equation that expresses the data points as a function of time since 2003, if possible. The units go up in years, so the rate of change over ten years.
+130536 We have the points (0, 7930) and (10, 9372) whrer 2003 = year "0" and 2013 = year "10"
The slope of a line through these points is given by :
[9372 - 7930] / [ 10 - 0] = 144.2 .....and this is the rate of change per year
The linear equation that models this is:
y = 144.2t + 7930
Where t represents the number of years after 2003
ok ill try XD;
2003 --> 2013 = 10 years
total change is 9372-7930 = 1442
1442/10 = change per year (if linear) = 144.2
if you take one year to be one value on the x line
and you take 1 (from the change value) to be on value in the y line
then rise/run = gradient
rise = 144.2
run = 1
therefore gradient = 144.2
equation of a line = mx + c = y
where m=gradient
x=x intercept
c=y intercept
so - y = 144.2x + 0
(as you said that the first point is 2003 - and therefore lies on the y axis)
I may be wrong
XD
+130536 We have the points (0, 7930) and (10, 9372) whrer 2003 = year "0" and 2013 = year "10"
The slope of a line through these points is given by :
[9372 - 7930] / [ 10 - 0] = 144.2 .....and this is the rate of change per year
The linear equation that models this is:
y = 144.2t + 7930
Where t represents the number of years after 2003
