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There are 13 female board members and 12 male board members. If a committee of 10 members is randomly chosen, what is the probability that the committee has exactly 5 females? Round your answer to 6 decimal places as needed.

 Jun 28, 2017
 #1
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We want choose any  5 of the 13 females  and any 5 of the 12 males =

 

C(13,5) * C(12,5)  = 1019304    (1)

 

And the total committees possible  =   C(25, 10) = 3268760    (2)

 

So the probability  =  (1)  / (2)  =   1019304 / 3268760  ≈  0.311832

 

 

cool cool cool

 Jun 28, 2017

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