How do you solve all of these?
t1 = 4(1) – 1 = 3
t2 = 4(2) – 1 = 7
t3 = 4(3) – 1 = 11
tn+1 = 4(n + 1) – 1 = 4n + 4 – 1 = 4n + 3
tn+1 – tn = [4n + 3] – [ 4(n) – 1] = 4
