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Siva starts at vertex A of square ABCD with side length 10. He walks towards vertex C, along the diagonal AC.  He then walks towards B, then towards D.  What is the length of his path?

 
 Oct 22, 2025

Best Answer 

 #1
avatar+2264 
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Siva starts at vertex A of square ABCD with side length 10. He walks towards vertex C, along the diagonal AC.  He then walks towards B, then towards D.  What is the length of his path?     

 

A to C (diag)     =  10 sqrt(2)  =  14.14     

C to B (side)     =  10              =  10.00     

B to D (diag)     =  10 sqrt(2)   =  14.14     

 

                                  total       =  38.28     

.     

 Oct 23, 2025
 #1
avatar+2264 
+1
Best Answer

 

Siva starts at vertex A of square ABCD with side length 10. He walks towards vertex C, along the diagonal AC.  He then walks towards B, then towards D.  What is the length of his path?     

 

A to C (diag)     =  10 sqrt(2)  =  14.14     

C to B (side)     =  10              =  10.00     

B to D (diag)     =  10 sqrt(2)   =  14.14     

 

                                  total       =  38.28     

.     

Bosco Oct 23, 2025

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