If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16, then what is the fourteenth term?
Let r be the common ratio
So
(-2)r^(5-2) = 16
(-2)r^3 = 16
r^3 = -16/2
r^3 = - 8
r = -2
So the 14th term is
(16)(-2)^(14 - 5)
16 (-2)^9
16 * (-512) =
-8192
+96 
